ret = context.subscribe_tick(symbol=self._symbol) if ret is not None: print(ret) tbpy.exit() ret = context.subscribe_bar(symbol=self._symbol, frequency='1m') if ret is not None: print(ret) tbpy.exit() self._account = context.subscribe_account(account_id=self._account_id) if self._account is None: print(tbpy.get_last_err()) tbpy.exit() self._timer_id = context.create_timer(interval_millsecs=5000) while tbpy.get_current_tick(symbol=self._symbol) is None: time.sleep(300) # 休眠5分钟 print('目前尚未开盘，请等待。') self._tick = tbpy.get_current_tick(symbol=self._symbol) print('1st tick:', self._tick)
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再怎么流控也不应该在on_init()里面限制啊。下面就是get_current_tick()之前的代码，我没看出哪个需要流控。
ret = context.subscribe_tick(symbol=self._symbol) if ret is not None: print(ret) tbpy.exit() ret = context.subscribe_bar(symbol=self._symbol, frequency='1m') if ret is not None: print(ret) tbpy.exit() self._account = context.subscribe_account(account_id=self._account_id) if self._account is None: print(tbpy.get_last_err()) tbpy.exit() self._timer_id = context.create_timer(interval_millsecs=5000) while tbpy.get_current_tick(symbol=self._symbol) is None: time.sleep(300) # 休眠5分钟 print('目前尚未开盘，请等待。') self._tick = tbpy.get_current_tick(symbol=self._symbol) print('1st tick:', self._tick)
自己顶一个，是因为当前tick没有报价造成整个tick对象返回None吗？ 如果是这种情况，官方是不是应该处理一下，返回上一个有效的tick对象之类的？